2x^2+24-49x=0

Solution for 2x^2+24-49x=0 equation:

2x^2+24-49x=0

a = 2; b = -49; c = +24;
Δ = b2-4ac
Δ = -492-4·2·24
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-47}{2*2}=\frac{2}{4}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+47}{2*2}=\frac{96}{4}
=24
$